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6x(3x+8)=16x

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Solution for 6x(3x+8)=16x equation:



6x(3x+8)=16x
We move all terms to the left:
6x(3x+8)-(16x)=0
We add all the numbers together, and all the variables
-16x+6x(3x+8)=0
We multiply parentheses
18x^2-16x+48x=0
We add all the numbers together, and all the variables
18x^2+32x=0
a = 18; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·18·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}

\sqrt{\Delta}=\sqrt{1024}=32
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*18}=\frac{-64}{36} =-1+7/9
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*18}=\frac{0}{36} =0

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