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6x(3x-36)=0
We multiply parentheses
18x^2-216x=0
a = 18; b = -216; c = 0;
Δ = b2-4ac
Δ = -2162-4·18·0
Δ = 46656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{46656}=216$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-216)-216}{2*18}=\frac{0}{36} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-216)+216}{2*18}=\frac{432}{36} =12 $
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