6x(3x-4)=-x(-8)

Solution for 6x(3x-4)=-x(-8) equation:

6x(3x-4)=-x(-8)

We move all terms to the left:

6x(3x-4)-(-x(-8))=0

We multiply parentheses

18x^2-24x-(-x(-8))=0


We calculate terms in parentheses: -(-x(-8)), so:

-x(-8)

We multiply parentheses

8x

Back to the equation:

-(8x)


We add all the numbers together, and all the variables

18x^2-32x=0

a = 18; b = -32; c = 0;
Δ = b2-4ac
Δ = -322-4·18·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-32}{2*18}=\frac{0}{36}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+32}{2*18}=\frac{64}{36}
=1+7/9
$