6x(3x-5)=2x(9x-3)

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Solution for 6x(3x-5)=2x(9x-3) equation: 



6x(3x-5)=2x(9x-3)

We move all terms to the left:

6x(3x-5)-(2x(9x-3))=0

We multiply parentheses

18x^2-30x-(2x(9x-3))=0



We calculate terms in parentheses: -(2x(9x-3)), so:

2x(9x-3)

We multiply parentheses

18x^2-6x

Back to the equation:

-(18x^2-6x)



We get rid of parentheses

18x^2-18x^2-30x+6x=0

We add all the numbers together, and all the variables

-24x=0

x=0/-24

x=0

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