6x(4-x)=-2x(3x-1)+14x

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Solution for 6x(4-x)=-2x(3x-1)+14x equation: 



6x(4-x)=-2x(3x-1)+14x

We move all terms to the left:

6x(4-x)-(-2x(3x-1)+14x)=0

We add all the numbers together, and all the variables

6x(-1x+4)-(-2x(3x-1)+14x)=0

We multiply parentheses

-6x^2+24x-(-2x(3x-1)+14x)=0



We calculate terms in parentheses: -(-2x(3x-1)+14x), so:

-2x(3x-1)+14x

We add all the numbers together, and all the variables

14x-2x(3x-1)

We multiply parentheses

-6x^2+14x+2x

We add all the numbers together, and all the variables

-6x^2+16x

Back to the equation:

-(-6x^2+16x)



We get rid of parentheses

-6x^2+6x^2-16x+24x=0

We add all the numbers together, and all the variables

8x=0

x=0/8

x=0

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