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6x(4x+5)-3x(5x-2)=3x(3x+5)+3(x+36)
We move all terms to the left:
6x(4x+5)-3x(5x-2)-(3x(3x+5)+3(x+36))=0
We multiply parentheses
24x^2-15x^2+30x+6x-(3x(3x+5)+3(x+36))=0
We calculate terms in parentheses: -(3x(3x+5)+3(x+36)), so:We add all the numbers together, and all the variables
3x(3x+5)+3(x+36)
We multiply parentheses
9x^2+15x+3x+108
We add all the numbers together, and all the variables
9x^2+18x+108
Back to the equation:
-(9x^2+18x+108)
9x^2+36x-(9x^2+18x+108)=0
We get rid of parentheses
9x^2-9x^2+36x-18x-108=0
We add all the numbers together, and all the variables
18x-108=0
We move all terms containing x to the left, all other terms to the right
18x=108
x=108/18
x=6
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