6x(4x-1)=15

Solution for 6x(4x-1)=15 equation:

6x(4x-1)=15

We move all terms to the left:

6x(4x-1)-(15)=0

We multiply parentheses

24x^2-6x-15=0

a = 24; b = -6; c = -15;
Δ = b2-4ac
Δ = -62-4·24·(-15)
Δ = 1476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1476}=\sqrt{36*41}=\sqrt{36}*\sqrt{41}=6\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6\sqrt{41}}{2*24}=\frac{6-6\sqrt{41}}{48}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6\sqrt{41}}{2*24}=\frac{6+6\sqrt{41}}{48}
$