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6x(5-x)+4x(4+x)+x(2x-4)=8(5x-1)
We move all terms to the left:
6x(5-x)+4x(4+x)+x(2x-4)-(8(5x-1))=0
We add all the numbers together, and all the variables
6x(-1x+5)+4x(x+4)+x(2x-4)-(8(5x-1))=0
We multiply parentheses
-6x^2+4x^2+2x^2+30x+16x-4x-(8(5x-1))=0
We calculate terms in parentheses: -(8(5x-1)), so:We add all the numbers together, and all the variables
8(5x-1)
We multiply parentheses
40x-8
Back to the equation:
-(40x-8)
42x-(40x-8)=0
We get rid of parentheses
42x-40x+8=0
We add all the numbers together, and all the variables
2x+8=0
We move all terms containing x to the left, all other terms to the right
2x=-8
x=-8/2
x=-4
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