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6x(5x+2)=112
We move all terms to the left:
6x(5x+2)-(112)=0
We multiply parentheses
30x^2+12x-112=0
a = 30; b = 12; c = -112;
Δ = b2-4ac
Δ = 122-4·30·(-112)
Δ = 13584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13584}=\sqrt{16*849}=\sqrt{16}*\sqrt{849}=4\sqrt{849}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{849}}{2*30}=\frac{-12-4\sqrt{849}}{60} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{849}}{2*30}=\frac{-12+4\sqrt{849}}{60} $
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