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6x(5x+5)=-8-2(x+12)
We move all terms to the left:
6x(5x+5)-(-8-2(x+12))=0
We multiply parentheses
30x^2+30x-(-8-2(x+12))=0
We calculate terms in parentheses: -(-8-2(x+12)), so:We get rid of parentheses
-8-2(x+12)
determiningTheFunctionDomain -2(x+12)-8
We multiply parentheses
-2x-24-8
We add all the numbers together, and all the variables
-2x-32
Back to the equation:
-(-2x-32)
30x^2+30x+2x+32=0
We add all the numbers together, and all the variables
30x^2+32x+32=0
a = 30; b = 32; c = +32;
Δ = b2-4ac
Δ = 322-4·30·32
Δ = -2816
Delta is less than zero, so there is no solution for the equation
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