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6x(5x-2)+12=30
We move all terms to the left:
6x(5x-2)+12-(30)=0
We add all the numbers together, and all the variables
6x(5x-2)-18=0
We multiply parentheses
30x^2-12x-18=0
a = 30; b = -12; c = -18;
Δ = b2-4ac
Δ = -122-4·30·(-18)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-48}{2*30}=\frac{-36}{60} =-3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+48}{2*30}=\frac{60}{60} =1 $
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