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6x(7+2x)=4x(2x-1)
We move all terms to the left:
6x(7+2x)-(4x(2x-1))=0
We add all the numbers together, and all the variables
6x(2x+7)-(4x(2x-1))=0
We multiply parentheses
12x^2+42x-(4x(2x-1))=0
We calculate terms in parentheses: -(4x(2x-1)), so:We get rid of parentheses
4x(2x-1)
We multiply parentheses
8x^2-4x
Back to the equation:
-(8x^2-4x)
12x^2-8x^2+42x+4x=0
We add all the numbers together, and all the variables
4x^2+46x=0
a = 4; b = 46; c = 0;
Δ = b2-4ac
Δ = 462-4·4·0
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-46}{2*4}=\frac{-92}{8} =-11+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+46}{2*4}=\frac{0}{8} =0 $
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