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6x(8x+3)=0
We multiply parentheses
48x^2+18x=0
a = 48; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·48·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*48}=\frac{-36}{96} =-3/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*48}=\frac{0}{96} =0 $
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