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6x(x+18)=9x
We move all terms to the left:
6x(x+18)-(9x)=0
We add all the numbers together, and all the variables
-9x+6x(x+18)=0
We multiply parentheses
6x^2-9x+108x=0
We add all the numbers together, and all the variables
6x^2+99x=0
a = 6; b = 99; c = 0;
Δ = b2-4ac
Δ = 992-4·6·0
Δ = 9801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9801}=99$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(99)-99}{2*6}=\frac{-198}{12} =-16+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(99)+99}{2*6}=\frac{0}{12} =0 $
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