6x(x+3)=4x+1

Solution for 6x(x+3)=4x+1 equation:

6x(x+3)=4x+1

We move all terms to the left:

6x(x+3)-(4x+1)=0

We multiply parentheses

6x^2+18x-(4x+1)=0

We get rid of parentheses

6x^2+18x-4x-1=0

We add all the numbers together, and all the variables

6x^2+14x-1=0

a = 6; b = 14; c = -1;
Δ = b2-4ac
Δ = 142-4·6·(-1)
Δ = 220
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{220}=\sqrt{4*55}=\sqrt{4}*\sqrt{55}=2\sqrt{55}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{55}}{2*6}=\frac{-14-2\sqrt{55}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{55}}{2*6}=\frac{-14+2\sqrt{55}}{12}
$