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6x(x+5)=5x+25
We move all terms to the left:
6x(x+5)-(5x+25)=0
We multiply parentheses
6x^2+30x-(5x+25)=0
We get rid of parentheses
6x^2+30x-5x-25=0
We add all the numbers together, and all the variables
6x^2+25x-25=0
a = 6; b = 25; c = -25;
Δ = b2-4ac
Δ = 252-4·6·(-25)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-35}{2*6}=\frac{-60}{12} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+35}{2*6}=\frac{10}{12} =5/6 $
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