6x(x+9)=9x+18

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Solution for 6x(x+9)=9x+18 equation:



6x(x+9)=9x+18
We move all terms to the left:
6x(x+9)-(9x+18)=0
We multiply parentheses
6x^2+54x-(9x+18)=0
We get rid of parentheses
6x^2+54x-9x-18=0
We add all the numbers together, and all the variables
6x^2+45x-18=0
a = 6; b = 45; c = -18;
Δ = b2-4ac
Δ = 452-4·6·(-18)
Δ = 2457
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{2457}=\sqrt{9*273}=\sqrt{9}*\sqrt{273}=3\sqrt{273}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-3\sqrt{273}}{2*6}=\frac{-45-3\sqrt{273}}{12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+3\sqrt{273}}{2*6}=\frac{-45+3\sqrt{273}}{12} $

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