6x(x-3)-(2x-1)(3x+5)=50

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Solution for 6x(x-3)-(2x-1)(3x+5)=50 equation: 



6x(x-3)-(2x-1)(3x+5)=50

We move all terms to the left:

6x(x-3)-(2x-1)(3x+5)-(50)=0

We multiply parentheses

6x^2-18x-(2x-1)(3x+5)-50=0

We multiply parentheses ..

6x^2-(+6x^2+10x-3x-5)-18x-50=0

We get rid of parentheses

6x^2-6x^2-10x+3x-18x+5-50=0

We add all the numbers together, and all the variables

-25x-45=0

We move all terms containing x to the left, all other terms to the right

-25x=45

x=45/-25

x=-1+4/5

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