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6x(x-4)=-12
We move all terms to the left:
6x(x-4)-(-12)=0
We add all the numbers together, and all the variables
6x(x-4)+12=0
We multiply parentheses
6x^2-24x+12=0
a = 6; b = -24; c = +12;
Δ = b2-4ac
Δ = -242-4·6·12
Δ = 288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{288}=\sqrt{144*2}=\sqrt{144}*\sqrt{2}=12\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-12\sqrt{2}}{2*6}=\frac{24-12\sqrt{2}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+12\sqrt{2}}{2*6}=\frac{24+12\sqrt{2}}{12} $
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