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6x(x-4)=90
We move all terms to the left:
6x(x-4)-(90)=0
We multiply parentheses
6x^2-24x-90=0
a = 6; b = -24; c = -90;
Δ = b2-4ac
Δ = -242-4·6·(-90)
Δ = 2736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2736}=\sqrt{144*19}=\sqrt{144}*\sqrt{19}=12\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-12\sqrt{19}}{2*6}=\frac{24-12\sqrt{19}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+12\sqrt{19}}{2*6}=\frac{24+12\sqrt{19}}{12} $
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