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6x+((29-5x)/8)+1=46
We move all terms to the left:
6x+((29-5x)/8)+1-(46)=0
We add all the numbers together, and all the variables
6x+((-5x+29)/8)+1-46=0
We add all the numbers together, and all the variables
6x+((-5x+29)/8)-45=0
We multiply all the terms by the denominator
6x*8)+((-5x+29)-45*8)=0
We add all the numbers together, and all the variables
6x*8)+((-5x+29)=0
Wy multiply elements
48x^2=0
a = 48; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·48·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{96}=0$
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