6x+((3x+2)/2)=61

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Solution for 6x+((3x+2)/2)=61 equation: 



6x+((3x+2)/2)=61

We move all terms to the left:

6x+((3x+2)/2)-(61)=0

We multiply all the terms by the denominator


6x*2)+((3x+2)-61*2)=0

We add all the numbers together, and all the variables

6x*2)+((3x+2)=0

Wy multiply elements

12x^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{24}=0$

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