6x+(1-2x)+(5x-3)+3x=2x+(17+4x+35)

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Solution for 6x+(1-2x)+(5x-3)+3x=2x+(17+4x+35) equation: 



6x+(1-2x)+(5x-3)+3x=2x+(17+4x+35)

We move all terms to the left:

6x+(1-2x)+(5x-3)+3x-(2x+(17+4x+35))=0

We add all the numbers together, and all the variables

6x+(-2x+1)+(5x-3)+3x-(2x+(4x+52))=0

We add all the numbers together, and all the variables

9x+(-2x+1)+(5x-3)-(2x+(4x+52))=0

We get rid of parentheses

9x-2x+5x-(2x+(4x+52))+1-3=0



We calculate terms in parentheses: -(2x+(4x+52)), so:

2x+(4x+52)

We get rid of parentheses

2x+4x+52

We add all the numbers together, and all the variables

6x+52

Back to the equation:

-(6x+52)



We add all the numbers together, and all the variables

12x-(6x+52)-2=0

We get rid of parentheses

12x-6x-52-2=0

We add all the numbers together, and all the variables

6x-54=0

We move all terms containing x to the left, all other terms to the right

6x=54

x=54/6

x=9

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