6x+(1-3x)=16-4(2x+1)

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Solution for 6x+(1-3x)=16-4(2x+1) equation: 



6x+(1-3x)=16-4(2x+1)

We move all terms to the left:

6x+(1-3x)-(16-4(2x+1))=0

We add all the numbers together, and all the variables

6x+(-3x+1)-(16-4(2x+1))=0

We get rid of parentheses

6x-3x-(16-4(2x+1))+1=0



We calculate terms in parentheses: -(16-4(2x+1)), so:

16-4(2x+1)

determiningTheFunctionDomain
-4(2x+1)+16

We multiply parentheses

-8x-4+16

We add all the numbers together, and all the variables

-8x+12

Back to the equation:

-(-8x+12)



We add all the numbers together, and all the variables

3x-(-8x+12)+1=0

We get rid of parentheses

3x+8x-12+1=0

We add all the numbers together, and all the variables

11x-11=0

We move all terms containing x to the left, all other terms to the right

11x=11

x=11/11

x=1

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