6x+(16-2x)=4(4+x)

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Solution for 6x+(16-2x)=4(4+x) equation: 



6x+(16-2x)=4(4+x)

We move all terms to the left:

6x+(16-2x)-(4(4+x))=0

We add all the numbers together, and all the variables

6x+(-2x+16)-(4(x+4))=0

We get rid of parentheses

6x-2x-(4(x+4))+16=0



We calculate terms in parentheses: -(4(x+4)), so:

4(x+4)

We multiply parentheses

4x+16

Back to the equation:

-(4x+16)



We add all the numbers together, and all the variables

4x-(4x+16)+16=0

We get rid of parentheses

4x-4x-16+16=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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