6x+(18+4x)=50-(12-5x)

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Solution for 6x+(18+4x)=50-(12-5x) equation: 



6x+(18+4x)=50-(12-5x)

We move all terms to the left:

6x+(18+4x)-(50-(12-5x))=0

We add all the numbers together, and all the variables

6x+(4x+18)-(50-(-5x+12))=0

We get rid of parentheses

6x+4x-(50-(-5x+12))+18=0



We calculate terms in parentheses: -(50-(-5x+12)), so:

50-(-5x+12)

determiningTheFunctionDomain
-(-5x+12)+50

We get rid of parentheses

5x-12+50

We add all the numbers together, and all the variables

5x+38

Back to the equation:

-(5x+38)



We add all the numbers together, and all the variables

10x-(5x+38)+18=0

We get rid of parentheses

10x-5x-38+18=0

We add all the numbers together, and all the variables

5x-20=0

We move all terms containing x to the left, all other terms to the right

5x=20

x=20/5

x=4

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