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6x+(2(3x))=100
We move all terms to the left:
6x+(2(3x))-(100)=0
determiningTheFunctionDomain 6x+23x-100=0
We add all the numbers together, and all the variables
29x-100=0
We move all terms containing x to the left, all other terms to the right
29x=100
x=100/29
x=3+13/29
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