6x+(3x+1)=20-(2x-3)

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Solution for 6x+(3x+1)=20-(2x-3) equation:



6x+(3x+1)=20-(2x-3)
We move all terms to the left:
6x+(3x+1)-(20-(2x-3))=0
We get rid of parentheses
6x+3x-(20-(2x-3))+1=0
We calculate terms in parentheses: -(20-(2x-3)), so:
20-(2x-3)
determiningTheFunctionDomain -(2x-3)+20
We get rid of parentheses
-2x+3+20
We add all the numbers together, and all the variables
-2x+23
Back to the equation:
-(-2x+23)
We add all the numbers together, and all the variables
9x-(-2x+23)+1=0
We get rid of parentheses
9x+2x-23+1=0
We add all the numbers together, and all the variables
11x-22=0
We move all terms containing x to the left, all other terms to the right
11x=22
x=22/11
x=2

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