6x+(4+x)*(x-4)=x*(x+2)-8*(2-x)

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Solution for 6x+(4+x)*(x-4)=x*(x+2)-8*(2-x) equation: 



6x+(4+x)(x-4)=x(x+2)-8(2-x)

We move all terms to the left:

6x+(4+x)(x-4)-(x(x+2)-8(2-x))=0

We add all the numbers together, and all the variables

6x+(x+4)(x-4)-(x(x+2)-8(-1x+2))=0

We use the square of the difference formula

x^2+6x-(x(x+2)-8(-1x+2))-16=0



We calculate terms in parentheses: -(x(x+2)-8(-1x+2)), so:

x(x+2)-8(-1x+2)

We multiply parentheses

x^2+2x+8x-16

We add all the numbers together, and all the variables

x^2+10x-16

Back to the equation:

-(x^2+10x-16)



We get rid of parentheses

x^2-x^2+6x-10x+16-16=0

We add all the numbers together, and all the variables

-4x=0

x=0/-4

x=0

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