6x+(4-2)=10+4x-8

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Solution for 6x+(4-2)=10+4x-8 equation: 



6x+(4-2)=10+4x-8

We move all terms to the left:

6x+(4-2)-(10+4x-8)=0

We add all the numbers together, and all the variables

6x-(4x+2)+2=0

We get rid of parentheses

6x-4x-2+2=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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