6x+(5(x/2)=48

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Solution for 6x+(5(x/2)=48 equation: 



6x+(5(x/2)=48

We move all terms to the left:

6x+(5(x/2)-(48)=0

We add all the numbers together, and all the variables

6x+(5(+x/2)-48=0

We multiply all the terms by the denominator


6x*2)-48+(5(+x=0

Wy multiply elements

12x^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{24}=0$

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