6x+1-3(-3x-1)=3(x-4)

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Solution for 6x+1-3(-3x-1)=3(x-4) equation:



6x+1-3(-3x-1)=3(x-4)
We move all terms to the left:
6x+1-3(-3x-1)-(3(x-4))=0
We multiply parentheses
6x+9x-(3(x-4))+3+1=0
We calculate terms in parentheses: -(3(x-4)), so:
3(x-4)
We multiply parentheses
3x-12
Back to the equation:
-(3x-12)
We add all the numbers together, and all the variables
15x-(3x-12)+4=0
We get rid of parentheses
15x-3x+12+4=0
We add all the numbers together, and all the variables
12x+16=0
We move all terms containing x to the left, all other terms to the right
12x=-16
x=-16/12
x=-1+1/3

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