6x+10(2x+4)=12(4x-10)+8

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Solution for 6x+10(2x+4)=12(4x-10)+8 equation: 



6x+10(2x+4)=12(4x-10)+8

We move all terms to the left:

6x+10(2x+4)-(12(4x-10)+8)=0

We multiply parentheses

6x+20x-(12(4x-10)+8)+40=0



We calculate terms in parentheses: -(12(4x-10)+8), so:

12(4x-10)+8

We multiply parentheses

48x-120+8

We add all the numbers together, and all the variables

48x-112

Back to the equation:

-(48x-112)



We add all the numbers together, and all the variables

26x-(48x-112)+40=0

We get rid of parentheses

26x-48x+112+40=0

We add all the numbers together, and all the variables

-22x+152=0

We move all terms containing x to the left, all other terms to the right

-22x=-152

x=-152/-22

x=6+10/11

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