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6x+10+(-3x)=4x*10*
We move all terms to the left:
6x+10+(-3x)-(4x*10*)=0
We add all the numbers together, and all the variables
6x+(-3x)-(+4x*10*)+10=0
We get rid of parentheses
6x-3x-4x*10*+10=0
We add all the numbers together, and all the variables
3x-4x*10*+10=0
Wy multiply elements
-40x^2+3x+10=0
a = -40; b = 3; c = +10;
Δ = b2-4ac
Δ = 32-4·(-40)·10
Δ = 1609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{1609}}{2*-40}=\frac{-3-\sqrt{1609}}{-80} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{1609}}{2*-40}=\frac{-3+\sqrt{1609}}{-80} $
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