6x+10=2(x-4)+2x+18

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Solution for 6x+10=2(x-4)+2x+18 equation: 



6x+10=2(x-4)+2x+18

We move all terms to the left:

6x+10-(2(x-4)+2x+18)=0



We calculate terms in parentheses: -(2(x-4)+2x+18), so:

2(x-4)+2x+18

We add all the numbers together, and all the variables

2x+2(x-4)+18

We multiply parentheses

2x+2x-8+18

We add all the numbers together, and all the variables

4x+10

Back to the equation:

-(4x+10)



We get rid of parentheses

6x-4x-10+10=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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