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6x+11=5+3(x+2)
We move all terms to the left:
6x+11-(5+3(x+2))=0
We calculate terms in parentheses: -(5+3(x+2)), so:We get rid of parentheses
5+3(x+2)
determiningTheFunctionDomain 3(x+2)+5
We multiply parentheses
3x+6+5
We add all the numbers together, and all the variables
3x+11
Back to the equation:
-(3x+11)
6x-3x-11+11=0
We add all the numbers together, and all the variables
3x=0
x=0/3
x=0
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