6x+12+3x-20=100

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Solution for 6x+12+3x-20=100 equation: 



6x+12+3x-20=100

We move all terms to the left:

6x+12+3x-20-(100)=0

We add all the numbers together, and all the variables

9x-108=0

We move all terms containing x to the left, all other terms to the right

9x=108

x=108/9

x=12

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