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6x+12=2(3x-6)+22
We move all terms to the left:
6x+12-(2(3x-6)+22)=0
We calculate terms in parentheses: -(2(3x-6)+22), so:We get rid of parentheses
2(3x-6)+22
We multiply parentheses
6x-12+22
We add all the numbers together, and all the variables
6x+10
Back to the equation:
-(6x+10)
6x-6x-10+12=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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