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6x+16-2x^2=8
We move all terms to the left:
6x+16-2x^2-(8)=0
We add all the numbers together, and all the variables
-2x^2+6x+8=0
a = -2; b = 6; c = +8;
Δ = b2-4ac
Δ = 62-4·(-2)·8
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-10}{2*-2}=\frac{-16}{-4} =+4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+10}{2*-2}=\frac{4}{-4} =-1 $
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