6x+16=3(230-32x)

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Solution for 6x+16=3(230-32x) equation: 



6x+16=3(230-32x)

We move all terms to the left:

6x+16-(3(230-32x))=0

We add all the numbers together, and all the variables

6x-(3(-32x+230))+16=0



We calculate terms in parentheses: -(3(-32x+230)), so:

3(-32x+230)

We multiply parentheses

-96x+690

Back to the equation:

-(-96x+690)



We get rid of parentheses

6x+96x-690+16=0

We add all the numbers together, and all the variables

102x-674=0

We move all terms containing x to the left, all other terms to the right

102x=674

x=674/102

x=6+31/51

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