6x+16=3(230-32x)

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Solution for 6x+16=3(230-32x) equation:



6x+16=3(230-32x)
We move all terms to the left:
6x+16-(3(230-32x))=0
We add all the numbers together, and all the variables
6x-(3(-32x+230))+16=0
We calculate terms in parentheses: -(3(-32x+230)), so:
3(-32x+230)
We multiply parentheses
-96x+690
Back to the equation:
-(-96x+690)
We get rid of parentheses
6x+96x-690+16=0
We add all the numbers together, and all the variables
102x-674=0
We move all terms containing x to the left, all other terms to the right
102x=674
x=674/102
x=6+31/51

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