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6x+18=9(x+2)-3x
We move all terms to the left:
6x+18-(9(x+2)-3x)=0
We calculate terms in parentheses: -(9(x+2)-3x), so:We get rid of parentheses
9(x+2)-3x
We add all the numbers together, and all the variables
-3x+9(x+2)
We multiply parentheses
-3x+9x+18
We add all the numbers together, and all the variables
6x+18
Back to the equation:
-(6x+18)
6x-6x-18+18=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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