6x+2(x+3)=-3(x+1)+14

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Solution for 6x+2(x+3)=-3(x+1)+14 equation: 



6x+2(x+3)=-3(x+1)+14

We move all terms to the left:

6x+2(x+3)-(-3(x+1)+14)=0

We multiply parentheses

6x+2x-(-3(x+1)+14)+6=0



We calculate terms in parentheses: -(-3(x+1)+14), so:

-3(x+1)+14

We multiply parentheses

-3x-3+14

We add all the numbers together, and all the variables

-3x+11

Back to the equation:

-(-3x+11)



We add all the numbers together, and all the variables

8x-(-3x+11)+6=0

We get rid of parentheses

8x+3x-11+6=0

We add all the numbers together, and all the variables

11x-5=0

We move all terms containing x to the left, all other terms to the right

11x=5

x=5/11

x=5/11

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