6x+2(x-1)=4(x+1)+10

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Solution for 6x+2(x-1)=4(x+1)+10 equation: 



6x+2(x-1)=4(x+1)+10

We move all terms to the left:

6x+2(x-1)-(4(x+1)+10)=0

We multiply parentheses

6x+2x-(4(x+1)+10)-2=0



We calculate terms in parentheses: -(4(x+1)+10), so:

4(x+1)+10

We multiply parentheses

4x+4+10

We add all the numbers together, and all the variables

4x+14

Back to the equation:

-(4x+14)



We add all the numbers together, and all the variables

8x-(4x+14)-2=0

We get rid of parentheses

8x-4x-14-2=0

We add all the numbers together, and all the variables

4x-16=0

We move all terms containing x to the left, all other terms to the right

4x=16

x=16/4

x=4

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