6x+2(x-5)=5(x+1)-4

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Solution for 6x+2(x-5)=5(x+1)-4 equation:



6x+2(x-5)=5(x+1)-4
We move all terms to the left:
6x+2(x-5)-(5(x+1)-4)=0
We multiply parentheses
6x+2x-(5(x+1)-4)-10=0
We calculate terms in parentheses: -(5(x+1)-4), so:
5(x+1)-4
We multiply parentheses
5x+5-4
We add all the numbers together, and all the variables
5x+1
Back to the equation:
-(5x+1)
We add all the numbers together, and all the variables
8x-(5x+1)-10=0
We get rid of parentheses
8x-5x-1-10=0
We add all the numbers together, and all the variables
3x-11=0
We move all terms containing x to the left, all other terms to the right
3x=11
x=11/3
x=3+2/3

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