6x+2-2(-8x-3)=6(x-1)

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Solution for 6x+2-2(-8x-3)=6(x-1) equation:



6x+2-2(-8x-3)=6(x-1)
We move all terms to the left:
6x+2-2(-8x-3)-(6(x-1))=0
We multiply parentheses
6x+16x-(6(x-1))+6+2=0
We calculate terms in parentheses: -(6(x-1)), so:
6(x-1)
We multiply parentheses
6x-6
Back to the equation:
-(6x-6)
We add all the numbers together, and all the variables
22x-(6x-6)+8=0
We get rid of parentheses
22x-6x+6+8=0
We add all the numbers together, and all the variables
16x+14=0
We move all terms containing x to the left, all other terms to the right
16x=-14
x=-14/16
x=-7/8

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