6x+2-4x=3(2x+1)-2(2x+1/2)

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Solution for 6x+2-4x=3(2x+1)-2(2x+1/2) equation: 



6x+2-4x=3(2x+1)-2(2x+1/2)

We move all terms to the left:

6x+2-4x-(3(2x+1)-2(2x+1/2))=0

We add all the numbers together, and all the variables

6x-4x-(3(2x+1)-2(+2x+1/2))+2=0

We add all the numbers together, and all the variables

2x-(3(2x+1)-2(+2x+1/2))+2=0

We multiply all the terms by the denominator


2x*2))-(3(2x+2x+1+1)-2(+2*2))=0

We add all the numbers together, and all the variables

2x*2))-(3(4x+2)-24)=0

We add all the numbers together, and all the variables

2x*2))-(3(4x=0

Wy multiply elements

4x^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$

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