6x+20-3*(4x+5)=8x-12*(x-1)-3x

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Solution for 6x+20-3*(4x+5)=8x-12*(x-1)-3x equation: 



6x+20-3(4x+5)=8x-12(x-1)-3x

We move all terms to the left:

6x+20-3(4x+5)-(8x-12(x-1)-3x)=0

We multiply parentheses

6x-12x-(8x-12(x-1)-3x)-15+20=0



We calculate terms in parentheses: -(8x-12(x-1)-3x), so:

8x-12(x-1)-3x

We add all the numbers together, and all the variables

5x-12(x-1)

We multiply parentheses

5x-12x+12

We add all the numbers together, and all the variables

-7x+12

Back to the equation:

-(-7x+12)



We add all the numbers together, and all the variables

-6x-(-7x+12)+5=0

We get rid of parentheses

-6x+7x-12+5=0

We add all the numbers together, and all the variables

x-7=0

We move all terms containing x to the left, all other terms to the right

x=7

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