6x+2=6(2/3x+3)

Solution for 6x+2=6(2/3x+3) equation:

6x+2=6(2/3x+3)

We move all terms to the left:

6x+2-(6(2/3x+3))=0


Domain of the equation: 3x+3))!=0

x∈R


We multiply all the terms by the denominator


6x*3x+2*3x+3))-(6(2+3))=0

We add all the numbers together, and all the variables

6x*3x+2*3x+3))-(65)=0

We add all the numbers together, and all the variables

6x*3x+2*3x=0

Wy multiply elements

18x^2+6x=0

a = 18; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·18·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*18}=\frac{-12}{36}
=-1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*18}=\frac{0}{36}
=0
$