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6x+2=8x^2
We move all terms to the left:
6x+2-(8x^2)=0
determiningTheFunctionDomain -8x^2+6x+2=0
a = -8; b = 6; c = +2;
Δ = b2-4ac
Δ = 62-4·(-8)·2
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-10}{2*-8}=\frac{-16}{-16} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+10}{2*-8}=\frac{4}{-16} =-1/4 $
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