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6x+2x(-4)x=-6
We move all terms to the left:
6x+2x(-4)x-(-6)=0
We add all the numbers together, and all the variables
6x+2x(-4)x+6=0
We multiply parentheses
-8x^2+6x+6=0
a = -8; b = 6; c = +6;
Δ = b2-4ac
Δ = 62-4·(-8)·6
Δ = 228
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{228}=\sqrt{4*57}=\sqrt{4}*\sqrt{57}=2\sqrt{57}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{57}}{2*-8}=\frac{-6-2\sqrt{57}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{57}}{2*-8}=\frac{-6+2\sqrt{57}}{-16} $
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